Question

If x=2/3 and x=-3 are the roots of quadratic equation ax^2+2ax+5x+10 then find the value of (a) and (b)​

Answer 1

p(x) = ax²+2ax +5x +10 =0

p(x) = ax² + x(2a+5) +10 = 0

p(-3) = a(-3)² -3(2a+5) +10 = 0

9a -6a-15 +10 =0

3a = 5

a = 5/3

p(2/3) = a(2/3)² -2/3(2a+5)+10 =0

= 4a/9 -4a/3- 10/3 +10 =0

-8a/3 = 10/3 -10

-8a/3 = -20/3

-8a = -20

a= 20/8

a= 5/2