Question

If x=2/3 and x=-3 are the roots of the equation ax²+7x+b=0, find the value of "a" and "b".

Answer 1

Sum of roots = - (co-efficient of x /co-efficient of x^2)= 7/a=2/3-3=-7/3hence a=-3
product of roots= (constant term /co-efficient of x^2)= b/a=b/-3=2/3*-3=-2 hence b=6