Question

If x=2/3 and x= -3 are the zeros
of the quadratic polynomial.
(1 Point)
ax+ 7x + b , then find the value
a= -6, b=-3
a = -6, b = -3
a = 6, b = -3
a = 3, b = -6​

Answer 1

Given

$\alpha = \frac{2}{3} \: \: and \: \: \beta = - 3$

So,

$\alpha + \beta = \frac{2}{3} + ( - 3) \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{2 - 9}{3} = \frac{ - 7}{3} \\ \\ \alpha \beta = \frac{2}{3} \times ( - 3) = - 2$

Therefore,

quadratic polynomial =

$= {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ = {x}^{2} - \frac{7}{3} x + ( - 2) \\ = 3 {x}^{2} - 7x - 6$

So,

a = 3 and b= -6

hope it will help u ✨☺️