if x=2/3 and x=-3 roots of the equation ax2 + bx + c = 0 find the value of a and b
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Answer:
7+3x-14 , or a=7 , b=3
Step-by-step explanation:
let p and q be roots of the equation \
given p = 2/3 , q-3
then c/a=p x q and -b/a = p+q
c/a = 2/3*3=2
-b/a=-7/3
Taking a = 7 ,
b=3 , c=-14(As 7 is the lowest possible value of "a" that will gives an integer as a solution for b and c)
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