Question

If x=-2/3 and y=1/4 find(x+y)÷(x-y)

Answer 1

Answer:

The value of the given expression is

$\frac{x+y}{x-y}=\frac{5}{11}$

Step-by-step explanation:

The values of the given variables are $x=\frac{-2}{3},y=\frac{1}{4}$ and we are required to find the value of the expression $\frac{x+y}{x-y}$ and we shall find it by the following way.

Substituting the value of variables in above expression,we get

$\frac{x+y}{x-y}=\frac{\frac{-2}{3} +\frac{1}{4} }{\frac{-2}{3} -\frac{1}{4} }$

The LCM becomes 12 in both the numerator and denominator of the expression.Hence we write it as

$\frac{\frac{-8+3}{12} }{\frac{-8-3}{12} } =\frac{-5}{-11}=\frac{5}{11}$

Therefore,the value of the given expression is

$\frac{x+y}{x-y}=\frac{5}{11}$

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Answer 2

The value of (x+y)÷(x-y) is 0.454545

Step-by-step explanation:

Given:

x = -2/3

y = 1/4

To find:

(x+y)÷(x-y)

Solution:

The value of x & y is given

So first we find the value of (x+y)

= ( -2/3 + 1/4)

$= -\frac{2}{3} +\frac{1}{4}$

The denominators of the fractions are not equal

So we use the cross multiplication method

$= \frac{-2(4)+1 (3)}{3 (4)}$

$= \frac{-8+3}{12}$

$= \frac{-5}{12}$

∴ (x + y) = -5/12

∴ (x+y) = - 0.41666667

Now, finding (x-y) using the same method

= ( -2/3 - 1/4)

$= -\frac{2}{3} -\frac{1}{4}$

$= \frac{-2(4)-1 (3)}{3 (4)}$

$= \frac{-8-3}{12}$

$= \frac{-11}{12}$

∴ (x-y) = -11/12

∴ (x-y) = - 0.91666667

Now, $\frac{x+y}{x-y} = \frac{-0.41666667}{-0.91666667}$

$= 0.454545$

∴ x + y    = 0.454545

  x - y

The value of (x+y)÷(x-y) is 0.454545

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