Math, asked by nandinilata881, 4 days ago

If x=2-√3, find the value of
(x +  \frac{1}{x} )^{3}  + 2(x +  \frac{1}{x} ) ^{2}  + (x +  \frac{1}{x} ) - 100

Answers

Answered by vikashpatnaik2009
3

Answer:

x=2−  

3

​  

⇒  

x

1

​  

=  

2−  

3

​  

 

1

​  

=2+  

3

​  

 

(x  

2

+  

x  

2

 

1

​  

)=(x+  

x

1

​  

)  

2

−2=(2−  

3

​  

+2+  

3

​  

)  

2

−2=14

(x  

2

−  

x  

2

 

1

​  

)=(x−  

x

1

​  

)(x+  

x

1

​  

)=(4×−2  

3

​  

)=−8  

3

​  

 

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