Math, asked by minatozakimazcho, 4 months ago

if x=2+✓3 find the value of (x+1÷1)³​

Answers

Answered by GPGAMER9128
0

((2 +  \sqrt{3})  + 1 \div 1) {}^{3}

(2 +  \sqrt{3}  + 1) {}^{3}

(3 +  \sqrt{3} ) {}^{3}

Using identity

(a+b)³ = a³ + b³ + 3a²b + 3ab²

(3) {}^{3}  +  (\sqrt{3}) {}^{3} + 3(3) {}^{2}( \sqrt{3}) + 3(3)( \sqrt{3} ){}^{2}

27 + 3 \sqrt{3}  + 27 \sqrt{3}  + 27

54 + 30 \sqrt{3}

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