if x=2+√3 find the value of x+1/x
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Given : x = ( 2 + √3 ) --------------- equation 1
So, 1 / x = 1 / ( 2 + √3 )
To rationalize it , multiply its numerator and denominator by ( 2 - √3 )
1 / x = 1 * ( 2 - √3 ) / ( 2 + √3 ) ( 2 - √3 )
By using identity ( a + b ) ( a - b ) = a² - b².
1 / x = ( 2 - √3 ) / { ( 2 )² - ( √3 )² }
1 / x = ( 2 - √3 ) / { 4 - 3 }
1 / x = ( 2 - √3 ) / 1
1 / x = ( 2 - √3 ) ----------------- equation 2.
By adding equation 1 and equation 2 ,
x + 1 / x = 2 + √3 + 2 - √3
x + 1 / x = 4.
Answer for this question is 4.
☺☺☺
Given : x = ( 2 + √3 ) --------------- equation 1
So, 1 / x = 1 / ( 2 + √3 )
To rationalize it , multiply its numerator and denominator by ( 2 - √3 )
1 / x = 1 * ( 2 - √3 ) / ( 2 + √3 ) ( 2 - √3 )
By using identity ( a + b ) ( a - b ) = a² - b².
1 / x = ( 2 - √3 ) / { ( 2 )² - ( √3 )² }
1 / x = ( 2 - √3 ) / { 4 - 3 }
1 / x = ( 2 - √3 ) / 1
1 / x = ( 2 - √3 ) ----------------- equation 2.
By adding equation 1 and equation 2 ,
x + 1 / x = 2 + √3 + 2 - √3
x + 1 / x = 4.
Answer for this question is 4.
☺☺☺
Answered by
0
X=2+root3
1÷x=1÷2+root3
Rationaliging=
1÷2+root3×2-root 3×2-root 3= 2-root3
Putting value=2+root3+2-root3=4
Answer=4
1÷x=1÷2+root3
Rationaliging=
1÷2+root3×2-root 3×2-root 3= 2-root3
Putting value=2+root3+2-root3=4
Answer=4
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