if x=2+✓3, find the value of x^3+1/x^3
Answers
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Answer:
Let p (x) = x + 1 / x = 2
Let p (x) = x + 1 / x = 2= x + 1 = 2x
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2
Let p (x) = x + 1 / x = 2= x + 1 = 2x= 2x - x = 1or, x = 1.let g(x) = x^3 + 1/x^3since, x = 1therefore,g (1) = (1)^3 +1 / (1)^3= 1 + 1 / 1= 2 / 1= 2So, the answer to your question is 2.