if x=2+ √3, find the value of x²+1/2x
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4
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Let see your answer !!!!
Given that
x = 2 + √3
x^2 + 1/x^2 = ?
Solution
1/x = 1/2 + √3
= 1 × (2 - √3) / (2 + √3) × (2 - √3)^2
= 2 - √3 / (2)^2 - (√3)^2
= 2 - √3 / 4 - 3
= 2 - √3
Therefore ,
x^2 + 1/x^2
= (2 + √3)^2 + (2 - √3)^2
= [(2)^2 + (√3)^2 + 2 × 2 × √3] + [(2)^2 + (√3)^2 - 2 × 2 × √3]
= [4 + 3 + 4√3] + [4 + 3 - 4√3]
= 7 + 4√3 + 7 - 4√3
= 14
Thanks :)))))
Let see your answer !!!!
Given that
x = 2 + √3
x^2 + 1/x^2 = ?
Solution
1/x = 1/2 + √3
= 1 × (2 - √3) / (2 + √3) × (2 - √3)^2
= 2 - √3 / (2)^2 - (√3)^2
= 2 - √3 / 4 - 3
= 2 - √3
Therefore ,
x^2 + 1/x^2
= (2 + √3)^2 + (2 - √3)^2
= [(2)^2 + (√3)^2 + 2 × 2 × √3] + [(2)^2 + (√3)^2 - 2 × 2 × √3]
= [4 + 3 + 4√3] + [4 + 3 - 4√3]
= 7 + 4√3 + 7 - 4√3
= 14
Thanks :)))))
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