Math, asked by varun306, 1 year ago

if x=2+√3, find the value
of x3

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Answered by ria113
3
Heya !!

Here's your answer.. ⬇⬇
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⚫ Given :- x = 2 + √3

⚫ To Find :- x³ + 1/x³ = ?

⚫ Solution :- x = 2 + √3

 \frac{1}{x}  =  \frac{1}{2 +  \sqrt{3} }  \\  \\  \frac{1}{x}  =  \frac{1}{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }  \\  \\  \frac{1}{x}  =   \frac{2 -  \sqrt{3} }{4 - 3}  \\   \\ \frac{1}{x}  = 2 -  \sqrt{3}  \\  \\ x +  \frac{1}{x}  = 2 +  \sqrt{3}  + 2 -  \sqrt{3}  \\  \\ x +  \frac{1}{x}  = 4 \\  \\ take \:  \: cube \:  \: on \:  \: both \:  \: side \\  \\  {(x +  \frac{1}{x} )}^{3}  =  {(4)}^{3}  \\  \\  {x}^{3}  +  \frac{1}{ {x}^{3} }  + 3x  \times \frac{1}{x} (x +  \frac{1}{x} ) = 64 \\  \\  {x}^{3}  +  \frac{1}{ {x}^{3} }  + 3(4) = 64 \:   \:  \:  \:  \: \:..... (x +  \frac{1}{x}  = 4) \\  \\  {x}^{3}  +  \frac{1}{ {x}^{3} }  = 64 - 12 \\  \\  {x}^{3}  +  \frac{1}{ {x}^{3} }  = 52 \\  \\
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Hope it helps..

Thanks :))

grvbundela008p3f6id: hey..!
grvbundela008p3f6id: this is nice :)
ria113: thanks both (:
grvbundela008p3f6id: can I ask u something Ria?
Answered by TheUrvashi
3
hope it helps to you.
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