Question

if x = -2/3 is a zero of a polynomial p(x)=27x cube - ax square - x - 3 then find the value of a

Answer 1

Answer:

a= -93/4

Step-by-step explanation:

x=-2/3

p(x)=27x³-ax²-x-3=0

=27(-2/3)³-a(-2/3)²-(-2/3)-3=0

=27(-8/27)-a(4/9)+(2/3)-3=0

=-8-$\frac{4a}{9}$+$\frac{2}{3}$-3=0

=$\frac{-72-4a+6-27}{9}$=0

=-72-4a+6-27=0

=-4a-93=0

4a=-93

a=-93/4

Answer 2

Step-by-step explanation:

I hope it helps thank you