Math, asked by mayank4996, 7 months ago

if x =2-√3, then find the value of x-1/x​

Answers

Answered by ayushkumarpanigrahi
1

Step-by-step explanation:

Given,

x = 2 -  \sqrt{3}

 \frac{1}{x}  =  \frac{1}{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }

 \frac{1}{x}  =  \frac{2 -{ \sqrt{3}}}{(2) {}^{2}  - ( \sqrt{3 {}^{2}) } }

 \frac{1}{x}  =  \frac{2 -  \sqrt{3} }{4 - 3}

 \frac{1}{x}  = 2 -  \sqrt{3}

Now,

x -  \frac{1}{x}

 = 2 +  \sqrt{3}  - 2 -  \sqrt{3}

 = 2 + 2

 = 4

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Answered by HarshRaj554
2

ANSWER:-

2 \sqrt{3}

SOLUTION:-

x→2-3 (Given)

  \frac{1}{x} = \frac{1}{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2  +  \sqrt{3} }  = 2 +  \sqrt{3}

Now,

x -  \frac{1}{x}  = 2 -  \sqrt{3}  - (2 +  \sqrt{3} ) \\  = 2 -  \sqrt{3}  - 2 -  \sqrt{3}   \\  = 2 - 2 -  \sqrt{3}  -  \sqrt{3}  \\  - 2 \sqrt{3}

Hence, our answer is 23.

Hope You Understood.

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