Question

. If x = 2-√3, then find the value of x2

Answer 1

Step-by-step explanation:

x=2-root3...(given)

x^2=(2-root3)^2

(a-b)^2=a^2-2ab+b^2...(formula)

(2-root3)^2=4-4root3+3.

Therefore value of x^2 is 4-4root3+3.

Answer 2

Answer:

HERE IS YOUR ANSWER.

Step-by-step explanation:

x = 2 - √(3)

X² = ?

x² = ( 2 - √(3) )

x² = ( 2 - √(3) )= 2² + √(3)² - 2 × 2 × √(3) --------[( a - b ) ² = a² + b² - 2ab ]

x² = ( 2 - √(3) )= 2² + √(3)² - 2 × 2 × √(3)= 4 + 3 - 4√(3)

= 7 - 4√(3)

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