Question

(if x= 2+3, y= 2-3, find the value of 3x2-5xy+3y2​

Answer 1

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Given , x = 2 + 3

y = 2 - 3

QUESTION:-

3x^2 - 5xy + 3y^2

● Solution :--

3 (2+3)^2 - 5(2+3) (2-3 ) + 3 (2-3)^3

= 3 { 4 + 12 + 9} - 5 {4 - 9} + 3 {4 - 12 + 9 }

= 3 × 25 - 5 × (-5) + 3 × 1

= 75 + 25 + 3

= 103. ( Answer)

Answer 2

Answer:

x=2+3

x=5

y= -1

3*5*2-5*5*-1+3*-1*2

30-25-7

5-7

= -2