Question

if x = 2 –√3, y = √3 –√7 and z= √7 –√4, find the value of x’ + y³+ z³



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Answer 1

Answer:

3(2 –√3)(√3 –√7)(√7 –2)

Step-by-step explanation:

x = 2 –√3

y = √3 –√7

z= √7 –√4 = √7 –2

∴ x + y + z = 2 –√3 + √3 –√7 + √7 –2 = 0

Using the identity x³ + y³ + z³ – 3xyz = (x + y + z)(x² +y² + z² −xy−yz−zx) = 0

∴  x’ + y³+ z³ = 3xyz

= 3(2 –√3)(√3 –√7)(√7 –2)