If x 2/3and x3 are roots of the quadratic equati0, find the values of a and b.
Answers
Answered by
0
If x = 2/3, x = -3 are roots, then the eqn will be
(x-2/3)(x-(-3))=0
⇒ (x-2/3)(x+3) = 0
⇒ x²-(2/3)x+3x-2 = 0
⇒ 3x²-2x+9x-6=0
⇒ 3x²+7x-6=0 is the required eqn.
Compare the eqn with ax²+7x+b=0
Therefore, a=3, b= -6
Read more on Brainly.in - https://brainly.in/question/1216197#readmore
(x-2/3)(x-(-3))=0
⇒ (x-2/3)(x+3) = 0
⇒ x²-(2/3)x+3x-2 = 0
⇒ 3x²-2x+9x-6=0
⇒ 3x²+7x-6=0 is the required eqn.
Compare the eqn with ax²+7x+b=0
Therefore, a=3, b= -6
Read more on Brainly.in - https://brainly.in/question/1216197#readmore
Similar questions