If x=2/3and x= -3 are the root of a quadratic equation X^2+ 7 x + b is equal to zero then find the value of a and b
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Answered by
2
x=2/3.. x= -3
Put value of x in quadratic equation
X^2 + 7x + b = 0
(-3)^2 + 7(-3) + b = 0
9 - 21 + b = 0
-12 +b = 0
b = 12..
[HOPE IT'S HELP U]
THANKS and best of luck for ur future :))
Put value of x in quadratic equation
X^2 + 7x + b = 0
(-3)^2 + 7(-3) + b = 0
9 - 21 + b = 0
-12 +b = 0
b = 12..
[HOPE IT'S HELP U]
THANKS and best of luck for ur future :))
Anonymous:
kya m tumhe kal dedu iska solution?? bcoz mummy ne bula liya
Answered by
3
Hii friend,
X = 2/3
PUTTING THE VALUE OF X IN EQUATION,
aX²+7X+b = 0
a×(2/3)²+ 7×2/3 + b = 0
a×4/9+14/3+b = 0
4a+42+9b/9 = 0
4a+42+9b = 0
4a+9b = -42
9b = -42-4a
b = -42-4a/9.......(1)
Again,
X = -3
PUTTING THE VALUE OF X IN EQUATION,
aX²+7X+b = 0
a×(-3)²+7×-3+b= 0
9a -21+b = 0
9a+b = 21
PUTTING THE VALUE OF B IN EQUATION,
9a+b = 21
9a+ (-42-4a/9) = 0
SOLVE THIS U WILL GET THE VALUE OF a. After finding the value of a put in equation (1). U WILL GET THE VALUE OF b..
HOPE YOU WILL UNDERSTAND THIS..
X = 2/3
PUTTING THE VALUE OF X IN EQUATION,
aX²+7X+b = 0
a×(2/3)²+ 7×2/3 + b = 0
a×4/9+14/3+b = 0
4a+42+9b/9 = 0
4a+42+9b = 0
4a+9b = -42
9b = -42-4a
b = -42-4a/9.......(1)
Again,
X = -3
PUTTING THE VALUE OF X IN EQUATION,
aX²+7X+b = 0
a×(-3)²+7×-3+b= 0
9a -21+b = 0
9a+b = 21
PUTTING THE VALUE OF B IN EQUATION,
9a+b = 21
9a+ (-42-4a/9) = 0
SOLVE THIS U WILL GET THE VALUE OF a. After finding the value of a put in equation (1). U WILL GET THE VALUE OF b..
HOPE YOU WILL UNDERSTAND THIS..
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