Question

if x+2 , 3x+1 and 4x+3 are arithmatice progresion then the value of x is -

Answer 1

if a, b, c. are in A.p. ; then

2b = a + c

so according to question

2(3x+1) = (x+2) +(4x+3)

6x + 2 = 5x +5

6x - 5x = 5 - 2

x = 3

hope it can help you ....,,,,✌✌✌✌

Answer 2

Hey there !!

A.P. (x+2) , (3x+1) , (4x+3) , ...

a = x+2

d = a2–a1
= (3x+1) – (x+2)
= 3x+1–x–2
= 2x – 1

OR

d = a3–a2
= (4x+3) – (3x+1)
= 4x+3–3x–1
= x + 2

So, a2–a1 = a3–a2
=> 2x – 1 = x + 2
=> 2x – x = 1 + 2
=> x = 3