if x 2-3x+2 is a factor of x4-ax2+b,then find the value of a,b
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x²-3x+2=0
x²-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
x=1,2
f(x)= x⁴-ax²+b
0=1-a+b
a-b=1
f(x)= x⁴-ax²+b
0=32-4a+b
4a-b=32
a=1+b
4(1+b)-b=32
4-4b-b=32
4-5b=32
-5b=32-4
b=-28/5
a+28/5=1
a=1-28/5
a=5-28/5
a=-23/5
x²-2x-x+2=0
x(x-2)-1(x-2)=0
(x-1)(x-2)=0
x=1,2
f(x)= x⁴-ax²+b
0=1-a+b
a-b=1
f(x)= x⁴-ax²+b
0=32-4a+b
4a-b=32
a=1+b
4(1+b)-b=32
4-4b-b=32
4-5b=32
-5b=32-4
b=-28/5
a+28/5=1
a=1-28/5
a=5-28/5
a=-23/5
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