If x^2 - 3x-4<0 then x lies in the interval...
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f(x)=X^2-3X-4<0
first solve the quadratic equation
f(x)=0 to get the 2 real roots .
since a-b+c=0,use shortcut.
The real roote are:x1=-1 and
x=-c/a=4/2=2
since a=1>0, the parabola graph open upward.Between the 2 real roots,f(x)<0as the graph stays below the x-axis.
Answer by open interval:(-1,2)
The 2 end points(critical points)aren't included in the solution set.
see the graph in the attachment please
hope it helps you:)
thank you
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