Question

If x^2+4x-1=0,then find the value of x+1/x

Answer 1

Answer:

${x}^{2} + 4x - 1 = 0 \\ the \: value \: of \: x \: are \\ x = \frac{ - 4 + \sqrt{20} }{2} = - 2 + \sqrt{5} \\ and \: x = - 2 - \sqrt{5} \\ the \: value \: of \frac{x + 1}{x} \\ \frac{ - 2 + \sqrt{5} + 1 }{ - 2 + \sqrt{5} } = \frac{ - 1 + \sqrt{5} }{ - 2 + \sqrt{5} } \\ and \\ \frac{ - 1 - \sqrt{5} }{ - 2 + \sqrt{5} }$

These values are the required answer

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

${x}^{2} + 4x - 1 = 0 \\ the \: value \: of \: - 1 = 0 \\ the \: value \: of \: x \: are \\ x = \frac{ - 4 + 20}{2} = - 2 + \sqrt{5} \\ and \: x = - 2 - \sqrt{5} \\ the \: value \: of \: \frac{x + 5}{x} \\ \frac{ - 2 + 5 + 1}{ - 2 + 5} = \frac{1 + \sqrt{5} }{ - 2 + \sqrt{5} } \\ and \: \frac{ - 1 - 5}{ - 2 + \sqrt{5} } \\ aree \: please \: bta \: tu \: merko \: thanks \: kyu\: kar \: raha \: hai$