Question

If x^2+4x+3 is lesser than or equal to 0, then what is the maximum value of x ?¿?¿​

Answer 1

x²+4x+3=0

⇒x²+x+3x+3=0

⇒x(x+1)+3(x+1)=0

⇒(x+1)(x+3)=0

Case-1

x+1=0

⇒x=0-1

⇒x=-1

∴(-1)²+4(-1)+3

=1-4+3

=0

case-2

x+3=0

⇒x=0-3

⇒x=-3

∴(-3)²+4(-3)+3

=9-12+3

=0

-3<-1

So, the maximum value of x is -1

Answer 2

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