Question

If x^2+4y^2=4xy find x:y

Answer 1

$x {}^{2} + 4y {}^{2} = 4xy \\ = > x {}^{2} - 2(x)(2y) + (2y) {}^{2} = 0\\ = > (x - 2y) {}^{2} = 0 \\ = > x - 2y = 0 \\ = > x = 2y \\ = > \frac{x}{y} = \frac{2}{1}$

therefore the ratio is =X:y=2:1

Answer 2

Answer:

2:1

Step-by-step explanation:

we have,,

x²+4y² = 4xy

x²+4y²-4xy = 0

(x-2y)² = 0

x-2y = 0

x = 2y

x/y = 2/1

so, x:y = 2:1 ....ans.