Question

If x^2+4y^2=4xy,Find x:y

Answer 1

$given - \\ {x}^{2} + 4 {y}^{2} = 4xy \\ {x}^{2} + {(2y)}^{2} - 4xy = 0 \\ {(x - 2y)}^{2} = 0 \\ x - 2y = 0 \\ x = 2y \\ \frac{x}{y } = 2$
✨x:y=2:1

Answer 2

x^2 + 4y^2 - 4xy = 0 
=> x^2 - 2 * x * 2y + (2y)^2 = 0 
=> (x-2y)^2 = 0 
=> x = 2y 
=> x/y = 2