If x=(2+√5)1/2+(2-√5)1/2&(2+√5)1/2-(2-√5)1/2 then evaluate x²+y². Do it in a simple way so That I can easily understand it..
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![x = (2 + \sqrt{5}) \times \frac{1}{2} + (2 - \sqrt{5} ) \frac{1}{2} \\ \: \: \: = \frac{2}{2} + \frac{ \sqrt{5} }{2} + \frac{2}{2} - \frac{ \sqrt{5} }{2} \\ \: \: \: \: \: \: \ = 2 \\similarly \: for \: y \: we \: have \: \\ y \: = \sqrt{5} \\ then \: x^{2} + {y}^{2} = 9 \\ i \: hope \: this \: will \: be \: helpful \: to \: you \: thank \: you \: x = (2 + \sqrt{5}) \times \frac{1}{2} + (2 - \sqrt{5} ) \frac{1}{2} \\ \: \: \: = \frac{2}{2} + \frac{ \sqrt{5} }{2} + \frac{2}{2} - \frac{ \sqrt{5} }{2} \\ \: \: \: \: \: \: \ = 2 \\similarly \: for \: y \: we \: have \: \\ y \: = \sqrt{5} \\ then \: x^{2} + {y}^{2} = 9 \\ i \: hope \: this \: will \: be \: helpful \: to \: you \: thank \: you \:](https://tex.z-dn.net/?f=x+%3D+%282+%2B++%5Csqrt%7B5%7D%29+++%5Ctimes++%5Cfrac%7B1%7D%7B2%7D++%2B+%282+-++%5Csqrt%7B5%7D+%29+%5Cfrac%7B1%7D%7B2%7D+%5C%5C+++%5C%3A++%5C%3A++%5C%3A++%3D++%5Cfrac%7B2%7D%7B2%7D++%2B++%5Cfrac%7B+%5Csqrt%7B5%7D+%7D%7B2%7D++%2B++%5Cfrac%7B2%7D%7B2%7D++-++%5Cfrac%7B+%5Csqrt%7B5%7D+%7D%7B2%7D++%5C%5C++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C%3A++%5C+%3D+2+%5C%5Csimilarly+%5C%3A+for+%5C%3A+y+%5C%3A+we+%5C%3A+have+%5C%3A++%5C%5C+y+%5C%3A++%3D++%5Csqrt%7B5%7D++%5C%5C+then+%5C%3A+x%5E%7B2%7D+++%2B++%7By%7D%5E%7B2%7D++%3D+9+%5C%5C+i+%5C%3A+hope+%5C%3A+this+%5C%3A+will+%5C%3A+be+%5C%3A+helpful+%5C%3A+to+%5C%3A+you+%5C%3A+thank+%5C%3A+you+%5C%3A+)
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