Math, asked by bloomingalchemy10, 10 months ago

if x= (2+√5), find the value of xsquare​

Answers

Answered by ksonakshi70
20

Answer:

x = (2 +  \sqrt{5} ) \\  x {}^{2}  \:  \:  \:  = (2 +  \sqrt{5} ) {}^{2}  \\ x {}^{2}  = \:  2 {}^{2}  + ( \sqrt{5} ) {}^{2}  + 2 \times 2 \times  \sqrt{5}  \\ x {}^{2}  \:  = 4 + 5 + 4 \sqrt{5}  \\ x {}^{2}  \:  = 9 + 4 \sqrt{5}

Answered by ravgersid555
4

Answer: 9+4√5

Step-by-step explanation:

given, x= (2+√5)

therefore x^{2} = (2+\sqrt{5} )^{2}\\ \\

(2^2+√5^2+2x2x√5)

= 4+5+4√5

= 9+4√5

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