if (x ^2 – 5) number of books weigh (2x^4 −4x^3 + 20x −50) kg, what is the weight of one book?
Answers
Answer:
Given weight of 6 books is 1.260 kg
⟹ weight of each book is
6
1.260
=0.210 kg
Let the number of books that will weigh 3.150 kg be x
as we know that
weight of x books is 0.210x kg
⟹0.210x=3.150
⟹x=
0.210
3.150
=15
Number of books is 15
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Given : (x ² – 5) number of books weigh (2x⁴−4x³ + 20x −50) kg,
To Find : what is the weight of one book
Solution:
weight of one book = y kg
Weight of (x ² – 5) number of books = (x ² – 5) y kg
books weigh (2x⁴−4x³ + 20x −50) kg,
= > (x ² – 5) y = (2x⁴−4x³ + 20x −50)
=> y = (2x⁴−4x³ + 20x −50) / (x ² – 5)
2x² -4x + 10
(x ² – 5) _| 2x⁴−4x³ + 20x −50 |_
2x⁴ - 10x²
_________
−4x³ + 10x² + 20x −50
−4x³ + 20x
______________________
+ 10x² −50
+ 10x² −50
_______________
0
Hence weight of one book is 2x² -4x + 10 kg
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