Math, asked by ryc1413, 1 year ago

If x^2+5x+6=0 then solve for x?
Please do it fast for braillinest

Answers

Answered by liza10987654321
1

 {x}^{2}  + 5x + 6 = 0 \\  \\  =  >  {x}^{2}  + 2x + 3x + 6 = 0 \\  \\  =  > x(x + 2) + 3(x + 2) = 0 \\  \\  =  > (x + 3)(x + 2) = 0 \\  \\  =  > x =  - 3 \:  \:  \: and \:  \: x =  - 2

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Answered by nomanmahmood34
0

Answer:

Step-by-step explanation:

x^2+3x+2x+6=0  (mmake a factor of 5x)

x(x+3)+2(x+3)=0 (Taking common x from first 2 values and 2from nect two values)

(x+3)(x+2)=0

either x+3=0 or x+2=0

x=-3 or x=-2

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