Math, asked by arjun238, 1 year ago

if x^2+5x+6+k=0 then the value of k for which roots of the given equation differ by 1

Answers

Answered by Sanchi1214
2
Hi
P(x) = X^2 +5x+6+k=0_(1)
Putting the value 1 in (1)equation.
P(1) = 1^2 +5*1+6+k=0
= 1+5+6+k =0
=6+6+k=0
12+k=0
K= - 12

HOPE YOU LIKE THE ANSWER!!!!!!!!

arjun238: its wrong
Sanchi1214: how
arjun238: ans is 0
Sanchi1214: when we will put the given value of k in the equation the answer will be 0
Similar questions