if x^2+5x+6+k=0 then the value of k for which roots of the given equation differ by 1
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Hi
P(x) = X^2 +5x+6+k=0_(1)
Putting the value 1 in (1)equation.
P(1) = 1^2 +5*1+6+k=0
= 1+5+6+k =0
=6+6+k=0
12+k=0
K= - 12
HOPE YOU LIKE THE ANSWER!!!!!!!!
P(x) = X^2 +5x+6+k=0_(1)
Putting the value 1 in (1)equation.
P(1) = 1^2 +5*1+6+k=0
= 1+5+6+k =0
=6+6+k=0
12+k=0
K= - 12
HOPE YOU LIKE THE ANSWER!!!!!!!!
arjun238:
its wrong
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