Question

If x-2 = 64, find the value of x^1/3 + x^0​

Answer 1

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$x - 2 = 64 \\ x = 64 + 2 \\ x = 66$

$\frac{ {x}^{1} }{3} + {x}^{0} \\ \\ \frac{ {66}^{1} }{3} + 1 \\ \\ \frac{66}{3} + 1 \\ \\ 22 + 1 \\ \\ 23$

Answer 2

Hope it's help you

x-2=64

x=64+2=66

So, put the value of x in eqn.

${66}^{1 \div 3} + {66}^{0}$

a⁰ = 1

${66}^{1 \div 3} + 1$

${a}^{m \div n} = \sqrt[n]{ {a}^{m} }$

$\sqrt[3]{66} + 1$

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