Question

if x^-2=64 find the value of x​

Answer 1

x^-2=64

x^-2=8^2

Now multiplying 1/2 on both sides of powers

(x^-2)1/2=(8^2)1/2

x^-1=8

Now by cross multiplying

1/8=1/x^-1

1/8=x

Now x^1/3+x^0

(1/8)^1/3+1

((1/2)^3)^1/3+1

1/2+1

3/2

Answer 2

Answer:

-x×-x= x^2

x=√64

x= 8

then,

x^1/3+x^0

8^1/3+8^0

8^0=1

{(1/2)^3}^1/3+1

1/2+1

(1+2)/2

3/2 is the correct answer.

option (C)

Step-by-step explanation:

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