Math, asked by 5102007study, 1 month ago

If x^-2 =64 then x ^1/2 + x ^0=

a. 2
b. 3
c. 3/2
d. 2/3​

Answers

Answered by jayeetaadhikari18751
1

Answer:

If x^-2 =64 then x ^1/2 + x ^0=c.3/2

We have to find the value of x^1/3+x^0

Step-by-step explanation:

x^-2=64

x^-2=8^2

Now multiplying 1/2 on both sides of powers

(x^-2)1/2=(8^2)1/2

x^-1=8

Now by cross multiplying

1/8=1/x^-1

1/8=x

Now x^1/3+x^0

(1/8)^1/3+1

(1/2)^3)^1/3+1

1/2+1

3/2

So, the answer is 3/2

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