Math, asked by skhullar2004129, 5 hours ago

if x^2 = 64 then x^1/3 + x^0​

Answers

Answered by samriddhasil297
0

Answer is 3 and -1

Step-by-step explanation:

x²=64

x= +8 or -8

at x=+8 (x)^⅓ + x⁰ = (8)^⅓ + 1 = 2+1 = 3

at x= -8. (x)^⅓ + x⁰ = (-8)^⅓ + 1 = -2+1 = -1

Answered by mridulbhargava2001
0

Answer:

x^2=64

so

√64=8

x=8

x^⅓+x^0

8^⅓+8^0

so

8^⅓+8^0=513

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