Question

If x^-2=64,then x^1/3+x^0=

Answer 1

Answer:

We have to find the value of x^1/3+x^0

Step-by-step explanation:

x^-2=64

x^-2=8^2

Now multiplying 1/2 on both sides of powers

(x^-2)1/2=(8^2)1/2

x^-1=8

Now by cross multiplying

1/8=1/x^-1

1/8=x

Now x^1/3+x^0

(1/8)^1/3+1

((1/2)^3)^1/3+1

1/2+1

3/2

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Answer 2

Concept:

A question of variable with the degree of variable 2 degree is called quadratic equation and it is written as

$a{x}^{2} + bx + c = 0$

Given :

We have given that

${x}^{ - 2} = 64$

Find :

We have to find the value of

${x}^{ \frac{1}{3} } + {x}^{0}$

Solution :

Consider given equation

${x}^{ - 2} = 64 \\ \frac{1}{ {x}^{ 2} } = 64 \\ {x}^{2} = \frac{1}{64} \\ x = \frac{1}{8}$

Calculating

${x}^{ \frac{1}{3} } + {x}^{0} ...(1)$

using the value of

$x$in equation

So,

${x}^{ \frac{1}{3} } + {x}^{0} \\ (\frac{1}{8}) {}^{ \frac{1}{3} } + 1 \\ \frac{1}{2} + 1 = \frac{3}{2}$

Hence, the correct answer is $\frac{3}{2}$.

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