Math, asked by saloniisharmaa24, 6 months ago

If x^-2=64, then x^(1/3)+x^0 is *

Answers

Answered by AnukshRana

1

Step-by-step explanation:

x*-2= 64

x= 64/2

-x= 32

x= -32

and x^(1/3)+x^0 is 0

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