Math, asked by gangwar8347dev, 11 months ago

if x^-2=64,then x^1/3+x^0 is equal to​

Answers

Answered by garvit3008
6

Step-by-step explanation:

x^-2=64

1/x²=64

x²=1/64

x=±1/8

x^1/3+x^0

³√x + x^0

³√1/8 + 1 (³√-1/8= undefined and x^0=1)

1/2+1

3/2

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