If x⁻² = 64, then x¹/³ + x⁰ =
A. 2
B. 3
C. 3/2
D. 2/3
Answers
Answered by
4
Given : x⁻² = 64
(1/x)² = 8²
[By the law of exponents , a-ⁿ = 1/a]
1/x = 8
x = 1/8
Then, x¹/³ + x⁰
= (⅛)¹/³ + (⅛)⁰
= (1/2³)¹/³ + 1
[By the law of exponents, a^0 = 1]
= ½ + 1
= (2 +1)/2
= 3/2
Hence, x¹/³ + x⁰ is 3/2 .
Option (C) 3/2 is correct.
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Answered by
1
x⁻² = 64
=>(1/x)² = 8²
=>1/x = 8
=>x = 1/8
Now,
x¹/³ + x⁰
putting the value of x
then,we get answer
= (⅛)¹/³ + (⅛)⁰
= (1/2³)¹/³ + 1
= ½ + 1
= (2 +1)/2
= 3/2
Thus, x¹/³ + x⁰ is 3/2
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