Question

if x+2=8;2y-3=5 and5z/3=-10, then the value of x+y-z​

Answer 1

Answer:

x=8-2=6

2y=5+3=8

 y= 8/2=4

5z=-10x3=-30

z=-6

x+y+z=6+4-6=4

Answer 2

Answer:

$\: \: \: \: \: \: \: \: x + 2 = 8 \\ = > x = 8 - 2 \\ = > x = 6 \\ \\ \: \: \: \: \: \: \: \: 2y - 3 = 5 \\ = > 2y = 5 + 3 \\ = > 2y = 8 \\ = > y = \frac{8}{2} \\ = > y = 4$

$\: \: \: \: \: \: \: \frac{5z}{3} = - 10 \\ = > 5z = 3 \times (- 10) \\ = > z = \frac{3 \times ( - 10)}{5} \\ = > z = 3 \times ( - 2) \\ = > z = - 6$

$x+y-z$

$6+4-(-6)$

$6+4+6$

$16$