Question

if x^2+9y^2=369 and xy=16 then find the value of x-3y​

Answer 1

Step-by-step explanation:

(x-3y)^2=x^2+9y^2-6xy

(x-3y)^2=369-6×16

(x-3y)^2=369-96

(x-3y)^2=273

x-3y=√273

So answer is √273