If x= -2 abd y= 3 then find the value of (-2x-3y)-(3y-2x)
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Answer:
-65
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(-2x-3y)-(3y-2x)
where x= -2 abd y= 3
(-2×-2 - 3×3 )-(3×3 - 2×-2 )
(4-9)-(9+4)
-5 × -13
65
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