Question

If x=2-alpha and y=2+ alpha is a solution of the equation 3x – 2y +6=0 find the value
of 'alpha'. Find three more solutions of the resultant equation.​

Answer 1

Answer:

Step-by-step explanation:given x=2-alpha and y=2+alpha

3(2-alpha) - 2(2 +alpha) +6=0

6-3alpha-4-2alpha+6=0

8-5alpha=0

-5alpha=-8

Alpha=-8/-5

Alpha =8/5

Answer 2

Given  : x=2–α   ,  y=2+α

 Equation :  3x–2y+6=0

To find : value  of α  

three more solutions of the resultant equation.​

Solution :

Lets put value of x & y

3(2–α) - 2(2+α) + 6 = 0

=> 6 - 3α - 4 - 2α + 6 = 0

=> 5α = 8

=> α = 1.6

x = 0.4

y = 3.6

3x - 2y + 6 = 0

x        y    

-4      3        

-2      0

0       3        

2       6

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