if x=2 & x=0 are the roots of the polynomial f(x)=2xcube - 5x square+ax+b find a&b
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hm it can be done by using both x =2 and 0 here's it follow
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kirat974:
Thank u it helps me a lot
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Answered by
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when x=2
f(x)=(2*2)^3-(5*2)^2+a*2+b
f(x)=4^3-10^2+2a+b
f(x)=64-100+2a+b
f(x)=-36+2a+b
when x=0
f(x)=(2*0)^3-(5*0)^2+a*0+b
f(x)=0-0+0a+b
f(x)=0a+b
now, -36+2a+b=0a+b
-36+2a-0a=b-b
-36+2a=0
-36=-2a
a=-36/-2
a=18.
I don't know how to find b.i tried my best to find a.
f(x)=(2*2)^3-(5*2)^2+a*2+b
f(x)=4^3-10^2+2a+b
f(x)=64-100+2a+b
f(x)=-36+2a+b
when x=0
f(x)=(2*0)^3-(5*0)^2+a*0+b
f(x)=0-0+0a+b
f(x)=0a+b
now, -36+2a+b=0a+b
-36+2a-0a=b-b
-36+2a=0
-36=-2a
a=-36/-2
a=18.
I don't know how to find b.i tried my best to find a.
actually it is my hw
your answer is wring according to x for multiply u donot get the question
u had done multiply lol its a x a variable
sorry! didn't get it
hm ok its right by the way by multiplying
well..kirat i'm sure my answer is correct
hm it is incorrect
it's correct
oh yeah yeah just realized my mistake you were right.
i know lol
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