if x=-2&x=3/4are the solutions to the equation hx^2+kx-6=0,find the value of h and k
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Answer:
very poor in maths bro what to do, sorry
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Step-by-step explanation:
putting x=2
4h+2k=6. ( dividing by 2 )
2h+k=3—(1)
putting x=3/4
9/16h+3/4k =6
36/16+3k=24
9/4h+3k=24
9h+12k=96—(2)
from eq (1),
h=3-k/2—(3)
putting in eq (2)
9(3-k/2)+12k=96
27-9k/2+12k=96
27-9k+24k=192
27+15k=192
15k=192-27
15k=165
k=11
putting k=11 in eq (3)
h=3-k/2
=3-11/2
-8/2
=-4
h=-4.
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