If (X+2)&(X+3) are factors of x³+ax+b find a and b
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here 's ur answer.......
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Sam1006:
Ty and its right answer
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(x+2)=0. x=-2
substitute x in given equation
-2²+a(-2)+b=0
-2a+b=-4. ---------(1)
(x+3)=0. x=-3
substitute x in given equation
-3²+a(-3)+b=0
-3a+b=-9. ---------(2)
By elimination method of 1 & 2 we get value of a as 5 and substituting a in any one equation we get value of b as 6
Therefore a=5 and b=6
Hope this answer will help you
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substitute x in given equation
-2²+a(-2)+b=0
-2a+b=-4. ---------(1)
(x+3)=0. x=-3
substitute x in given equation
-3²+a(-3)+b=0
-3a+b=-9. ---------(2)
By elimination method of 1 & 2 we get value of a as 5 and substituting a in any one equation we get value of b as 6
Therefore a=5 and b=6
Hope this answer will help you
plz mark this answer as brainliest
Read the question properly dear friend
sorry i thought it as x²
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