Question

if x=2,& x=3 are root of the equation 3x^2-2kx+2m=0 then find the value of k and m.​

Answer 1

Answer:

x=2

3(4)-2k(2)+2m=0

12-4k+2m=0......... (1)

x=3

3x(9)-2k(3)+2m=0

27-6k+2m=0........(2)

Subtracting equation (1) from (2)

27-6k+2m=0

12-4k+2m=0

(-) (+) (-)

15-2k=0

-2k=-15

K=15/2

Putting value of k in equation 1

12-4(15/2)+2m=0

-30+2m=-12

2m=-12+30

2m=18

m=9

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Answer 2

Answer:

required answer k=15/2 and m=9