If x=2 &y=1 is the solution of the linear equation 2x+3y+k=0, find the value of k
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2(2)+3(1)+k=0
K=4+3
K=7
K=4+3
K=7
Answered by
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2*2+3*1+k =0
4+3+k=0
k= -7
4+3+k=0
k= -7
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