If (x-2) and (2x-1) are the factors of ax^2 + 5X + b. Show that a-b=0
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FIRST
[X-2] = 0 AND [2X-1] = 0
X = 2 2X=1 ==> X = 1/2
SO,
P[2] = A[2]²+5[2] + B
P[2] = 4A + 10 + B
==> 4A+B = -10 ..................[1]
P[1/2] = A[1/2]²+5[1/2]
A/4 + 2.5 + B = 0
A+4B/4 = -2.5
A+4B = -10.0......................[2]
EQ [2] FROM [1]
4A+B = -10
A +4B = -10
MULTIPLY eq[2] by 4
4A+B = -10
4A+16B = -10
==> 16B = 0
==> B = 0
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