If (x+2)and (x-1) are factors of the polynomial 10x^2+px+q then pq is
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Answer:
x+2=0
x=-2
10(-2)^2+p(-2)+q=0
40-2p+q=0
2p+q=-40
-(2p-q)=-40
2p-q =40 _____(1)
x-1=0
x=1
10(1)+p(1)+q=0
10+p+q=0
p+q=-10______(2)
2×(2)-(1)
q=-20
p=30
pq= 30×-20=-600
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