If (x+2) and (x-1) are factors of (x^3+10x^2+mx+n
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1
Answer:
7 and-18
Step-by-step explanation:
Here, x+2 is a factor of x
3
+10x
2
+mx + n
x=−2
(−2)
3
+10(−2)
2
+m(−2)+n=0
−8+40=2m−n
2m−n=32 . (i)
Again, x−1 is a factor of x
3
+10x
2
+mx+n
x=1
1+10+m+n=0
m+n=−11 .(ii)
Adding (i) and (ii). we get,
3m=21
m=7
By putting m in (i). we get,
2(7)−n=32
−n=18
n=−18
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